115244353133303 has 4 divisors (see below), whose sum is σ = 115263022239288. Its totient is φ = 115225684027320.

The previous prime is 115244353133197. The next prime is 115244353133317. The reversal of 115244353133303 is 303331353442511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115244353133303 - 2⁸ = 115244353133047 is a prime.

It is a super-2 number, since 2×115244353133303² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115244353133323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9334543733 + ... + 9334556078.

It is an arithmetic number, because the mean of its divisors is an integer number (28815755559822).

Almost surely, 2^{115244353133303} is an apocalyptic number.

115244353133303 is a deficient number, since it is larger than the sum of its proper divisors (18669105985).

115244353133303 is an equidigital number, since it uses as much as digits as its factorization.

115244353133303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18669105984.

The product of its (nonzero) digits is 583200, while the sum is 41.

The spelling of 115244353133303 in words is "one hundred fifteen trillion, two hundred forty-four billion, three hundred fifty-three million, one hundred thirty-three thousand, three hundred three".