1152443701 has 2 divisors, whose sum is σ = 1152443702. Its totient is φ = 1152443700.

The previous prime is 1152443687. The next prime is 1152443717. The reversal of 1152443701 is 1073442511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1040062500 + 112381201 = 32250^2 + 10601^2 .

It is a cyclic number.

It is not a de Polignac number, because 1152443701 - 2¹⁹ = 1151919413 is a prime.

It is a super-3 number, since 3×1152443701³ (a number of 28 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1152443701.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1152443771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576221850 + 576221851.

It is an arithmetic number, because the mean of its divisors is an integer number (576221851).

Almost surely, 2^1152443701 is an apocalyptic number.

It is an amenable number.

1152443701 is a deficient number, since it is larger than the sum of its proper divisors (1).

1152443701 is an equidigital number, since it uses as much as digits as its factorization.

1152443701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 28.

The square root of 1152443701 is about 33947.6612007366. The cubic root of 1152443701 is about 1048.4311267020.

It can be divided in two parts, 11524 and 43701, that added together give a square (55225 = 235²).

The spelling of 1152443701 in words is "one billion, one hundred fifty-two million, four hundred forty-three thousand, seven hundred one".