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115251334105 = 523050266821
BaseRepresentation
bin110101101010110000…
…0111100101111011001
3102000111001201101111211
41223111200330233121
53342013320142410
6124540140023121
711220015114265
oct1532540745731
9360431641454
10115251334105
1144972412156
121a405531aa1
13ab394474ab
1458147cb0a5
152ee814868a
hex1ad583cbd9

115251334105 has 4 divisors (see below), whose sum is σ = 138301600932. Its totient is φ = 92201067280.

The previous prime is 115251334067. The next prime is 115251334111. The reversal of 115251334105 is 501433152511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 24876544729 + 90374789376 = 157723^2 + 300624^2 .

It is not a de Polignac number, because 115251334105 - 223 = 115242945497 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11525133406 + ... + 11525133415.

It is an arithmetic number, because the mean of its divisors is an integer number (34575400233).

Almost surely, 2115251334105 is an apocalyptic number.

It is an amenable number.

115251334105 is a deficient number, since it is larger than the sum of its proper divisors (23050266827).

115251334105 is an equidigital number, since it uses as much as digits as its factorization.

115251334105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23050266826.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 115251334105 its reverse (501433152511), we get a palindrome (616684486616).

The spelling of 115251334105 in words is "one hundred fifteen billion, two hundred fifty-one million, three hundred thirty-four thousand, one hundred five".

Divisors: 1 5 23050266821 115251334105