Base | Representation |
---|---|
bin | 110101101010110000… |
… | …1010110110111101011 |
3 | 102000111001220211022202 |
4 | 1223111201112313223 |
5 | 3342013332104011 |
6 | 124540142210415 |
7 | 11220016041311 |
oct | 1532541266753 |
9 | 360431824282 |
10 | 115251441131 |
11 | 44972485602 |
12 | 1a405583a0b |
13 | ab39484118 |
14 | 58148180b1 |
15 | 2ee816a23b |
hex | 1ad5856deb |
115251441131 has 2 divisors, whose sum is σ = 115251441132. Its totient is φ = 115251441130.
The previous prime is 115251441103. The next prime is 115251441161. The reversal of 115251441131 is 131144152511.
It is a weak prime.
It is an emirp because it is prime and its reverse (131144152511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115251441131 - 214 = 115251424747 is a prime.
It is a super-2 number, since 2×1152514411312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115251441094 and 115251441103.
It is not a weakly prime, because it can be changed into another prime (115251441101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57625720565 + 57625720566.
It is an arithmetic number, because the mean of its divisors is an integer number (57625720566).
Almost surely, 2115251441131 is an apocalyptic number.
115251441131 is a deficient number, since it is larger than the sum of its proper divisors (1).
115251441131 is an equidigital number, since it uses as much as digits as its factorization.
115251441131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2400, while the sum is 29.
Adding to 115251441131 its reverse (131144152511), we get a palindrome (246395593642).
The spelling of 115251441131 in words is "one hundred fifteen billion, two hundred fifty-one million, four hundred forty-one thousand, one hundred thirty-one".
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