Base | Representation |
---|---|
bin | 110101101010110000… |
… | …1010110110111001111 |
3 | 102000111001220211021201 |
4 | 1223111201112313033 |
5 | 3342013332103403 |
6 | 124540142210331 |
7 | 11220016041241 |
oct | 1532541266717 |
9 | 360431824251 |
10 | 115251441103 |
11 | 44972485587 |
12 | 1a4055839a7 |
13 | ab394840c6 |
14 | 5814818091 |
15 | 2ee816a21d |
hex | 1ad5856dcf |
115251441103 has 2 divisors, whose sum is σ = 115251441104. Its totient is φ = 115251441102.
The previous prime is 115251441101. The next prime is 115251441131. The reversal of 115251441103 is 301144152511.
It is a happy number.
It is an a-pointer prime, because the next prime (115251441131) can be obtained adding 115251441103 to its sum of digits (28).
It is a weak prime.
It is an emirp because it is prime and its reverse (301144152511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115251441103 - 21 = 115251441101 is a prime.
Together with 115251441101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115251441101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57625720551 + 57625720552.
It is an arithmetic number, because the mean of its divisors is an integer number (57625720552).
Almost surely, 2115251441103 is an apocalyptic number.
115251441103 is a deficient number, since it is larger than the sum of its proper divisors (1).
115251441103 is an equidigital number, since it uses as much as digits as its factorization.
115251441103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 115251441103 its reverse (301144152511), we get a palindrome (416395593614).
The spelling of 115251441103 in words is "one hundred fifteen billion, two hundred fifty-one million, four hundred forty-one thousand, one hundred three".
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