11525234432533 has 4 divisors (see below), whose sum is σ = 11527180282528. Its totient is φ = 11523288582540.

The previous prime is 11525234432527. The next prime is 11525234432581. The reversal of 11525234432533 is 33523443252511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11525234432533 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11525234432533.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11525234432513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 972916113 + ... + 972927958.

It is an arithmetic number, because the mean of its divisors is an integer number (2881795070632).

Almost surely, 2^{11525234432533} is an apocalyptic number.

It is an amenable number.

11525234432533 is a deficient number, since it is larger than the sum of its proper divisors (1945849995).

11525234432533 is an equidigital number, since it uses as much as digits as its factorization.

11525234432533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1945849994.

The product of its digits is 1296000, while the sum is 43.

The spelling of 11525234432533 in words is "eleven trillion, five hundred twenty-five billion, two hundred thirty-four million, four hundred thirty-two thousand, five hundred thirty-three".