Base | Representation |
---|---|
bin | 11010001101001001000111… |
… | …000101010101001001010111 |
3 | 120010002000110002022010122012 |
4 | 122031021013011111021113 |
5 | 110101243300310004120 |
6 | 1045042110225254435 |
7 | 33163464356426021 |
oct | 3215110705251127 |
9 | 503060402263565 |
10 | 115252345000535 |
11 | 337a5277148576 |
12 | 10b1481519441b |
13 | 4c403321c4392 |
14 | 206635971d011 |
15 | d4cea0a5d1c5 |
hex | 68d247155257 |
115252345000535 has 32 divisors (see below), whose sum is σ = 146693384121600. Its totient is φ = 86684248707840.
The previous prime is 115252345000523. The next prime is 115252345000577. The reversal of 115252345000535 is 535000543252511.
It is not a de Polignac number, because 115252345000535 - 210 = 115252344999511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115252345000492 and 115252345000501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1447667 + ... + 15251243.
It is an arithmetic number, because the mean of its divisors is an integer number (4584168253800).
Almost surely, 2115252345000535 is an apocalyptic number.
115252345000535 is a deficient number, since it is larger than the sum of its proper divisors (31441039121065).
115252345000535 is a wasteful number, since it uses less digits than its factorization.
115252345000535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13804271.
The product of its (nonzero) digits is 450000, while the sum is 41.
The spelling of 115252345000535 in words is "one hundred fifteen trillion, two hundred fifty-two billion, three hundred forty-five million, five hundred thirty-five", and thus it is an aban number.
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