11525320354633 has 4 divisors (see below), whose sum is σ = 11543244648208. Its totient is φ = 11507396061060.

The previous prime is 11525320354631. The next prime is 11525320354651. The reversal of 11525320354633 is 33645302352511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11525320354633 - 2¹ = 11525320354631 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11525320354633.

It is not an unprimeable number, because it can be changed into a prime (11525320354631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8962145823 + ... + 8962147108.

It is an arithmetic number, because the mean of its divisors is an integer number (2885811162052).

Almost surely, 2^{11525320354633} is an apocalyptic number.

It is an amenable number.

11525320354633 is a deficient number, since it is larger than the sum of its proper divisors (17924293575).

11525320354633 is an equidigital number, since it uses as much as digits as its factorization.

11525320354633 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17924293574.

The product of its (nonzero) digits is 972000, while the sum is 43.

The spelling of 11525320354633 in words is "eleven trillion, five hundred twenty-five billion, three hundred twenty million, three hundred fifty-four thousand, six hundred thirty-three".