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115265147 is a prime number
BaseRepresentation
bin1101101111011…
…00111001111011
322000220002001112
412313230321323
5214001441042
615234310535
72566510664
oct667547173
9260802045
10115265147
115a078458
123272844b
131ab59a3a
141144636b
15a1bc982
hex6dece7b

115265147 has 2 divisors, whose sum is σ = 115265148. Its totient is φ = 115265146.

The previous prime is 115265141. The next prime is 115265149. The reversal of 115265147 is 741562511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 115265147 - 24 = 115265131 is a prime.

It is a super-2 number, since 2×1152651472 = 26572108225863218, which contains 22 as substring.

Together with 115265149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (115265141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57632573 + 57632574.

It is an arithmetic number, because the mean of its divisors is an integer number (57632574).

Almost surely, 2115265147 is an apocalyptic number.

115265147 is a deficient number, since it is larger than the sum of its proper divisors (1).

115265147 is an equidigital number, since it uses as much as digits as its factorization.

115265147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8400, while the sum is 32.

The square root of 115265147 is about 10736.1607197359. The cubic root of 115265147 is about 486.6678639386.

The spelling of 115265147 in words is "one hundred fifteen million, two hundred sixty-five thousand, one hundred forty-seven".