Base | Representation |
---|---|
bin | 10101011110001000… |
… | …11100110110010101 |
3 | 1002202100022001220002 |
4 | 22233010130312111 |
5 | 142101420123013 |
6 | 5143454021045 |
7 | 555436565513 |
oct | 125704346625 |
9 | 32670261802 |
10 | 11527114133 |
11 | 4985834507 |
12 | 22984a7785 |
13 | 11191b3cc2 |
14 | 7b4cc34b3 |
15 | 476eb1358 |
hex | 2af11cd95 |
11527114133 has 2 divisors, whose sum is σ = 11527114134. Its totient is φ = 11527114132.
The previous prime is 11527114111. The next prime is 11527114211. The reversal of 11527114133 is 33141172511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6545295409 + 4981818724 = 80903^2 + 70582^2 .
It is a cyclic number.
It is not a de Polignac number, because 11527114133 - 26 = 11527114069 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11527114096 and 11527114105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11527114633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5763557066 + 5763557067.
It is an arithmetic number, because the mean of its divisors is an integer number (5763557067).
Almost surely, 211527114133 is an apocalyptic number.
It is an amenable number.
11527114133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11527114133 is an equidigital number, since it uses as much as digits as its factorization.
11527114133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2520, while the sum is 29.
Adding to 11527114133 its reverse (33141172511), we get a palindrome (44668286644).
The spelling of 11527114133 in words is "eleven billion, five hundred twenty-seven million, one hundred fourteen thousand, one hundred thirty-three".
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