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11527403243047 is a prime number
BaseRepresentation
bin1010011110111110111011…
…0001101000011000100111
31111211000020112220101001121
42213233232301220120213
53002331110212234142
640303341013234411
72266553540605606
oct247575661503047
944730215811047
1011527403243047
11374482068050a
121362108032a07
1365804c95b133
142bbd01da7a3d
1514ecc2e76c67
hexa7beec68627

11527403243047 has 2 divisors, whose sum is σ = 11527403243048. Its totient is φ = 11527403243046.

The previous prime is 11527403243009. The next prime is 11527403243063. The reversal of 11527403243047 is 74034230472511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11527403243047 - 231 = 11525255759399 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11527403242994 and 11527403243012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11527403243747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5763701621523 + 5763701621524.

It is an arithmetic number, because the mean of its divisors is an integer number (5763701621524).

Almost surely, 211527403243047 is an apocalyptic number.

11527403243047 is a deficient number, since it is larger than the sum of its proper divisors (1).

11527403243047 is an equidigital number, since it uses as much as digits as its factorization.

11527403243047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 564480, while the sum is 43.

The spelling of 11527403243047 in words is "eleven trillion, five hundred twenty-seven billion, four hundred three million, two hundred forty-three thousand, forty-seven".