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11529295153 is a prime number
BaseRepresentation
bin10101011110011001…
…10001010100110001
31002202111101212200121
422233030301110301
5142102444421103
65144012450241
7555464251255
oct125714612461
932674355617
1011529295153
114986a94102
122299179981
13111979894c
147b52d0265
154772926bd
hex2af331531

11529295153 has 2 divisors, whose sum is σ = 11529295154. Its totient is φ = 11529295152.

The previous prime is 11529295147. The next prime is 11529295213. The reversal of 11529295153 is 35159292511.

11529295153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7578921249 + 3950373904 = 87057^2 + 62852^2 .

It is a cyclic number.

It is not a de Polignac number, because 11529295153 - 25 = 11529295121 is a prime.

It is not a weakly prime, because it can be changed into another prime (11529295553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5764647576 + 5764647577.

It is an arithmetic number, because the mean of its divisors is an integer number (5764647577).

Almost surely, 211529295153 is an apocalyptic number.

It is an amenable number.

11529295153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11529295153 is an equidigital number, since it uses as much as digits as its factorization.

11529295153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 121500, while the sum is 43.

The spelling of 11529295153 in words is "eleven billion, five hundred twenty-nine million, two hundred ninety-five thousand, one hundred fifty-three".