Base | Representation |
---|---|
bin | 11010001101110101110001… |
… | …100100000010010001111111 |
3 | 120010020121020022111001020221 |
4 | 122031311301210002101333 |
5 | 110103040004344124210 |
6 | 1045120121101322211 |
7 | 33200112656142010 |
oct | 3215656144022177 |
9 | 503217208431227 |
10 | 115300302333055 |
11 | 33813646881284 |
12 | 10b21b79b66367 |
13 | 4c44a059cb008 |
14 | 20687c8a49007 |
15 | d4e35ae131da |
hex | 68dd7190247f |
115300302333055 has 16 divisors (see below), whose sum is σ = 158271599185920. Its totient is φ = 78990329320992.
The previous prime is 115300302333011. The next prime is 115300302333061. The reversal of 115300302333055 is 550333203003511.
It is a cyclic number.
It is not a de Polignac number, because 115300302333055 - 27 = 115300302332927 is a prime.
It is a super-2 number, since 2×1153003023330552 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 115300302333055.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1515276745 + ... + 1515352834.
It is an arithmetic number, because the mean of its divisors is an integer number (9891974949120).
Almost surely, 2115300302333055 is an apocalyptic number.
115300302333055 is a deficient number, since it is larger than the sum of its proper divisors (42971296852865).
115300302333055 is a wasteful number, since it uses less digits than its factorization.
115300302333055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3030630678.
The product of its (nonzero) digits is 60750, while the sum is 34.
Adding to 115300302333055 its reverse (550333203003511), we get a palindrome (665633505336566).
The spelling of 115300302333055 in words is "one hundred fifteen trillion, three hundred billion, three hundred two million, three hundred thirty-three thousand, fifty-five".
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