115300501113235 has 4 divisors (see below), whose sum is σ = 138360601335888. Its totient is φ = 92240400890584.

The previous prime is 115300501113067. The next prime is 115300501113241. The reversal of 115300501113235 is 532311105003511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115300501113235 - 2³⁹ = 114750745299347 is a prime.

It is a super-3 number, since 3×115300501113235³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115300501113197 and 115300501113206.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11530050111319 + ... + 11530050111328.

It is an arithmetic number, because the mean of its divisors is an integer number (34590150333972).

Almost surely, 2^{115300501113235} is an apocalyptic number.

115300501113235 is a deficient number, since it is larger than the sum of its proper divisors (23060100222653).

115300501113235 is an equidigital number, since it uses as much as digits as its factorization.

115300501113235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23060100222652.

The product of its (nonzero) digits is 6750, while the sum is 31.

Adding to 115300501113235 its reverse (532311105003511), we get a palindrome (647611606116746).

The spelling of 115300501113235 in words is "one hundred fifteen trillion, three hundred billion, five hundred one million, one hundred thirteen thousand, two hundred thirty-five".