Base | Representation |
---|---|
bin | 1010011111001010100101… |
… | …0010001110110010001001 |
3 | 1111211022022121212112100221 |
4 | 2213302221102032302021 |
5 | 3002404012240213423 |
6 | 40305015313030041 |
7 | 2300024224565626 |
oct | 247625122166211 |
9 | 44738277775327 |
10 | 11530532351113 |
11 | 3746086a03736 |
12 | 136283bb55321 |
13 | 65842b008179 |
14 | 2bc11b7bb34d |
15 | 14ee07a1ee5d |
hex | a7ca948ec89 |
11530532351113 has 6 divisors (see below), whose sum is σ = 12248696996126. Its totient is φ = 10852265741952.
The previous prime is 11530532351111. The next prime is 11530532351141. The reversal of 11530532351113 is 31115323503511.
It can be written as a sum of positive squares in 3 ways, for example, as 5961083390089 + 5569448961024 = 2441533^2 + 2359968^2 .
It is not a de Polignac number, because 11530532351113 - 21 = 11530532351111 is a prime.
It is a super-3 number, since 3×115305323511133 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11530532351111) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 19949017620 + ... + 19949018197.
Almost surely, 211530532351113 is an apocalyptic number.
It is an amenable number.
11530532351113 is a deficient number, since it is larger than the sum of its proper divisors (718164645013).
11530532351113 is an equidigital number, since it uses as much as digits as its factorization.
11530532351113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39898035851 (or 39898035834 counting only the distinct ones).
The product of its (nonzero) digits is 20250, while the sum is 34.
Adding to 11530532351113 its reverse (31115323503511), we get a palindrome (42645855854624).
The spelling of 11530532351113 in words is "eleven trillion, five hundred thirty billion, five hundred thirty-two million, three hundred fifty-one thousand, one hundred thirteen".
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