Base | Representation |
---|---|
bin | 1010011111001010100101… |
… | …0110000011001111100111 |
3 | 1111211022022200202101220111 |
4 | 2213302221112003033213 |
5 | 3002404013014234143 |
6 | 40305015350313451 |
7 | 2300024236236121 |
oct | 247625126031747 |
9 | 44738280671814 |
10 | 11530533352423 |
11 | 3746087527a68 |
12 | 1362840358887 |
13 | 65842b298b67 |
14 | 2bc11b99c211 |
15 | 14ee07b6b99d |
hex | a7ca95833e7 |
11530533352423 has 2 divisors, whose sum is σ = 11530533352424. Its totient is φ = 11530533352422.
The previous prime is 11530533352399. The next prime is 11530533352439. The reversal of 11530533352423 is 32425333503511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11530533352423 - 241 = 9331510096871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11530533352483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5765266676211 + 5765266676212.
It is an arithmetic number, because the mean of its divisors is an integer number (5765266676212).
Almost surely, 211530533352423 is an apocalyptic number.
11530533352423 is a deficient number, since it is larger than the sum of its proper divisors (1).
11530533352423 is an equidigital number, since it uses as much as digits as its factorization.
11530533352423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486000, while the sum is 40.
Adding to 11530533352423 its reverse (32425333503511), we get a palindrome (43955866855934).
The spelling of 11530533352423 in words is "eleven trillion, five hundred thirty billion, five hundred thirty-three million, three hundred fifty-two thousand, four hundred twenty-three".
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