Base | Representation |
---|---|
bin | 1010011111001010100101… |
… | …0110000011011100011011 |
3 | 1111211022022200202110000212 |
4 | 2213302221112003130123 |
5 | 3002404013014300433 |
6 | 40305015350321335 |
7 | 2300024236241402 |
oct | 247625126033433 |
9 | 44738280673025 |
10 | 11530533353243 |
11 | 3746087528643 |
12 | 136284035924b |
13 | 65842b299348 |
14 | 2bc11b99c639 |
15 | 14ee07b6bd48 |
hex | a7ca958371b |
11530533353243 has 2 divisors, whose sum is σ = 11530533353244. Its totient is φ = 11530533353242.
The previous prime is 11530533353237. The next prime is 11530533353321. The reversal of 11530533353243 is 34235333503511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11530533353243 - 214 = 11530533336859 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11530533353243.
It is not a weakly prime, because it can be changed into another prime (11530532353243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5765266676621 + 5765266676622.
It is an arithmetic number, because the mean of its divisors is an integer number (5765266676622).
Almost surely, 211530533353243 is an apocalyptic number.
11530533353243 is a deficient number, since it is larger than the sum of its proper divisors (1).
11530533353243 is an equidigital number, since it uses as much as digits as its factorization.
11530533353243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 729000, while the sum is 41.
Adding to 11530533353243 its reverse (34235333503511), we get a palindrome (45765866856754).
The spelling of 11530533353243 in words is "eleven trillion, five hundred thirty billion, five hundred thirty-three million, three hundred fifty-three thousand, two hundred forty-three".
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