1153100131 has 2 divisors, whose sum is σ = 1153100132. Its totient is φ = 1153100130.

The previous prime is 1153100129. The next prime is 1153100161. The reversal of 1153100131 is 1310013511.

It is a weak prime.

It is an emirp because it is prime and its reverse (1310013511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1153100131 - 2¹ = 1153100129 is a prime.

It is a super-2 number, since 2×1153100131² = 2659279824224434322, which contains 22 as substring.

Together with 1153100129, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1153100161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576550065 + 576550066.

It is an arithmetic number, because the mean of its divisors is an integer number (576550066).

Almost surely, 2^1153100131 is an apocalyptic number.

1153100131 is the 21477-th centered pentagonal number.

1153100131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153100131 is an equidigital number, since it uses as much as digits as its factorization.

1153100131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 16.

The square root of 1153100131 is about 33957.3280898247. The cubic root of 1153100131 is about 1048.6301504562.

Adding to 1153100131 its reverse (1310013511), we get a palindrome (2463113642).

The spelling of 1153100131 in words is "one billion, one hundred fifty-three million, one hundred thousand, one hundred thirty-one".