Base | Representation |
---|---|
bin | 10101011110100110… |
… | …11001111000100111 |
3 | 1002202121200020010221 |
4 | 22233103121320213 |
5 | 142103421043101 |
6 | 5144114025211 |
7 | 555515113240 |
oct | 125723317047 |
9 | 32677606127 |
10 | 11531034151 |
11 | 4987a7169a |
12 | 2299878207 |
13 | 1119c57340 |
14 | 7b5623cc7 |
15 | 4774d7aa1 |
hex | 2af4d9e27 |
11531034151 has 16 divisors (see below), whose sum is σ = 14270471488. Its totient is φ = 9073036800.
The previous prime is 11531034149. The next prime is 11531034157. The reversal of 11531034151 is 15143013511.
It is a cyclic number.
It is not a de Polignac number, because 11531034151 - 21 = 11531034149 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11531034157) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 333570 + ... + 366511.
It is an arithmetic number, because the mean of its divisors is an integer number (891904468).
Almost surely, 211531034151 is an apocalyptic number.
11531034151 is a deficient number, since it is larger than the sum of its proper divisors (2739437337).
11531034151 is a wasteful number, since it uses less digits than its factorization.
11531034151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 700282.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 11531034151 its reverse (15143013511), we get a palindrome (26674047662).
The spelling of 11531034151 in words is "eleven billion, five hundred thirty-one million, thirty-four thousand, one hundred fifty-one".
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