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1153114241351 = 19139436620311
BaseRepresentation
bin10000110001111010111…
…101101111100101000111
311002020101111212210100212
4100301322331233211013
5122343034221210401
62241422224030035
7146211150221102
oct20617275574507
94066344783325
101153114241351
1140503aa22726
1216759376231b
1384979abb257
143db4d65b739
151eedd953dbb
hex10c7af6f947

1153114241351 has 8 divisors (see below), whose sum is σ = 1222536873600. Its totient is φ = 1084564850040.

The previous prime is 1153114241299. The next prime is 1153114241353. The reversal of 1153114241351 is 1531424113511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1153114241351 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1153114241353) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218307515 + ... + 218312796.

It is an arithmetic number, because the mean of its divisors is an integer number (152817109200).

Almost surely, 21153114241351 is an apocalyptic number.

1153114241351 is a deficient number, since it is larger than the sum of its proper divisors (69422632249).

1153114241351 is a wasteful number, since it uses less digits than its factorization.

1153114241351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 436620469.

The product of its digits is 7200, while the sum is 32.

Adding to 1153114241351 its reverse (1531424113511), we get a palindrome (2684538354862).

The spelling of 1153114241351 in words is "one trillion, one hundred fifty-three billion, one hundred fourteen million, two hundred forty-one thousand, three hundred fifty-one".

Divisors: 1 19 139 2641 436620311 8295785909 60690223229 1153114241351