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11531298353 is a prime number
BaseRepresentation
bin10101011110101000…
…11010011000110001
31002202122011122120012
422233110122120301
5142104003021403
65144123424305
7555520263431
oct125724323061
932678148505
1011531298353
114988132143
122299985095
13111a01a683
147b56922c1
1547753aed8
hex2af51a631

11531298353 has 2 divisors, whose sum is σ = 11531298354. Its totient is φ = 11531298352.

The previous prime is 11531298323. The next prime is 11531298367. The reversal of 11531298353 is 35389213511.

11531298353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11413076224 + 118222129 = 106832^2 + 10873^2 .

It is a cyclic number.

It is not a de Polignac number, because 11531298353 - 214 = 11531281969 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11531298353.

It is not a weakly prime, because it can be changed into another prime (11531298313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5765649176 + 5765649177.

It is an arithmetic number, because the mean of its divisors is an integer number (5765649177).

Almost surely, 211531298353 is an apocalyptic number.

It is an amenable number.

11531298353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11531298353 is an equidigital number, since it uses as much as digits as its factorization.

11531298353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 97200, while the sum is 41.

The spelling of 11531298353 in words is "eleven billion, five hundred thirty-one million, two hundred ninety-eight thousand, three hundred fifty-three".