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1153132111042 = 2576566055521
BaseRepresentation
bin10000110001111100000…
…001111010010011000010
311002020102202111122222021
4100301330001322103002
5122343103310023132
62241424103032054
7146211455135242
oct20617401722302
94066382448867
101153132111042
1140504a01846a
1216759973b62a
1384980706b32
143db51b8db22
151eee02d3997
hex10c7c07a4c2

1153132111042 has 4 divisors (see below), whose sum is σ = 1729698166566. Its totient is φ = 576566055520.

The previous prime is 1153132111037. The next prime is 1153132111091. The reversal of 1153132111042 is 2401112313511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1081077983001 + 72054128041 = 1039749^2 + 268429^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1153132110998 and 1153132111016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 288283027759 + ... + 288283027762.

Almost surely, 21153132111042 is an apocalyptic number.

1153132111042 is a deficient number, since it is larger than the sum of its proper divisors (576566055524).

1153132111042 is an equidigital number, since it uses as much as digits as its factorization.

1153132111042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 576566055523.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 1153132111042 its reverse (2401112313511), we get a palindrome (3554244424553).

The spelling of 1153132111042 in words is "one trillion, one hundred fifty-three billion, one hundred thirty-two million, one hundred eleven thousand, forty-two".

Divisors: 1 2 576566055521 1153132111042