Base | Representation |
---|---|
bin | 10000110001111100001… |
… | …010000101000000100111 |
3 | 11002020102220112102220122 |
4 | 100301330022011000213 |
5 | 122343104332031241 |
6 | 2241424220552155 |
7 | 146211512263304 |
oct | 20617412050047 |
9 | 4066386472818 |
10 | 1153134252071 |
11 | 40505025000a |
12 | 16759a3b265b |
13 | 84980ca6509 |
14 | 3db5218a0ab |
15 | 1eee05a804b |
hex | 10c7c285027 |
1153134252071 has 4 divisors (see below), whose sum is σ = 1158214138872. Its totient is φ = 1148054365272.
The previous prime is 1153134251959. The next prime is 1153134252077. The reversal of 1153134252071 is 1702524313511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1153134252071 - 218 = 1153133989927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1153134252077) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2539943060 + ... + 2539943513.
It is an arithmetic number, because the mean of its divisors is an integer number (289553534718).
Almost surely, 21153134252071 is an apocalyptic number.
1153134252071 is a deficient number, since it is larger than the sum of its proper divisors (5079886801).
1153134252071 is an equidigital number, since it uses as much as digits as its factorization.
1153134252071 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5079886800.
The product of its (nonzero) digits is 25200, while the sum is 35.
Adding to 1153134252071 its reverse (1702524313511), we get a palindrome (2855658565582).
The spelling of 1153134252071 in words is "one trillion, one hundred fifty-three billion, one hundred thirty-four million, two hundred fifty-two thousand, seventy-one".
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