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11531402119973 is a prime number
BaseRepresentation
bin1010011111001101110100…
…1000001000101100100101
31111211101120020111100221102
42213303131020020230211
53002412302420314343
640305241503125445
72300054615524121
oct247633510105445
944741506440842
1011531402119973
11374649296797a
121362a432a3885
136585392785b8
142bc1a1108581
1514ee590793b8
hexa7cdd208b25

11531402119973 has 2 divisors, whose sum is σ = 11531402119974. Its totient is φ = 11531402119972.

The previous prime is 11531402119961. The next prime is 11531402120033. The reversal of 11531402119973 is 37991120413511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11519120604289 + 12281515684 = 3393983^2 + 110822^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11531402119973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11531402115973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5765701059986 + 5765701059987.

It is an arithmetic number, because the mean of its divisors is an integer number (5765701059987).

Almost surely, 211531402119973 is an apocalyptic number.

It is an amenable number.

11531402119973 is a deficient number, since it is larger than the sum of its proper divisors (1).

11531402119973 is an equidigital number, since it uses as much as digits as its factorization.

11531402119973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 47.

The spelling of 11531402119973 in words is "eleven trillion, five hundred thirty-one billion, four hundred two million, one hundred nineteen thousand, nine hundred seventy-three".