Base | Representation |
---|---|
bin | 11010001110000011110110… |
… | …001010110110111011001011 |
3 | 120010022001020022222212221220 |
4 | 122032003312022312323023 |
5 | 110103311430433121210 |
6 | 1045131100254133123 |
7 | 33201156260214300 |
oct | 3216036612667313 |
9 | 503261208885856 |
10 | 115315412004555 |
11 | 33819a9a8a00a4 |
12 | 10b24a961b11a3 |
13 | 4c46273195a39 |
14 | 206941d65b0a7 |
15 | d4e94268cc70 |
hex | 68e0f62b6ecb |
115315412004555 has 48 divisors (see below), whose sum is σ = 214699154252544. Its totient is φ = 52698108227520.
The previous prime is 115315412004553. The next prime is 115315412004587. The reversal of 115315412004555 is 555400214513511.
It is not a de Polignac number, because 115315412004555 - 21 = 115315412004553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (115315412004553) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 23840007 + ... + 28266176.
It is an arithmetic number, because the mean of its divisors is an integer number (4472899046928).
Almost surely, 2115315412004555 is an apocalyptic number.
115315412004555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
115315412004555 is a deficient number, since it is larger than the sum of its proper divisors (99383742247989).
115315412004555 is a wasteful number, since it uses less digits than its factorization.
115315412004555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52109216 (or 52109209 counting only the distinct ones).
The product of its (nonzero) digits is 300000, while the sum is 42.
The spelling of 115315412004555 in words is "one hundred fifteen trillion, three hundred fifteen billion, four hundred twelve million, four thousand, five hundred fifty-five".
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