Base | Representation |
---|---|
bin | 10101011110101110… |
… | …00101101100100101 |
3 | 1002202200111022002111 |
4 | 22233113011230211 |
5 | 142104143000122 |
6 | 5144150441021 |
7 | 555526245235 |
oct | 125727055445 |
9 | 32680438074 |
10 | 11532000037 |
11 | 4988571348 |
12 | 229a063171 |
13 | 111a204b7c |
14 | 7b57d5cc5 |
15 | 477628d77 |
hex | 2af5c5b25 |
11532000037 has 2 divisors, whose sum is σ = 11532000038. Its totient is φ = 11532000036.
The previous prime is 11531999981. The next prime is 11532000047. The reversal of 11532000037 is 73000023511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11371876321 + 160123716 = 106639^2 + 12654^2 .
It is a cyclic number.
It is not a de Polignac number, because 11532000037 - 215 = 11531967269 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11531999981 and 11532000017.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11532000047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766000018 + 5766000019.
It is an arithmetic number, because the mean of its divisors is an integer number (5766000019).
Almost surely, 211532000037 is an apocalyptic number.
It is an amenable number.
11532000037 is a deficient number, since it is larger than the sum of its proper divisors (1).
11532000037 is an equidigital number, since it uses as much as digits as its factorization.
11532000037 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 630, while the sum is 22.
Adding to 11532000037 its reverse (73000023511), we get a palindrome (84532023548).
The spelling of 11532000037 in words is "eleven billion, five hundred thirty-two million, thirty-seven", and thus it is an aban number.
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