Base | Representation |
---|---|
bin | 10101011110101110… |
… | …01011011001101010 |
3 | 1002202200112111010212 |
4 | 22233113023121222 |
5 | 142104144222102 |
6 | 5144151141122 |
7 | 555526403324 |
oct | 125727133152 |
9 | 32680474125 |
10 | 11532023402 |
11 | 4988587959 |
12 | 229a0747a2 |
13 | 111a2126b3 |
14 | 7b5800614 |
15 | 477630c52 |
hex | 2af5cb66a |
11532023402 has 4 divisors (see below), whose sum is σ = 17298035106. Its totient is φ = 5766011700.
The previous prime is 11532023401. The next prime is 11532023411. The reversal of 11532023402 is 20432023511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11316491641 + 215531761 = 106379^2 + 14681^2 .
It is not an unprimeable number, because it can be changed into a prime (11532023401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2883005849 + ... + 2883005852.
Almost surely, 211532023402 is an apocalyptic number.
11532023402 is a deficient number, since it is larger than the sum of its proper divisors (5766011704).
11532023402 is an equidigital number, since it uses as much as digits as its factorization.
11532023402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5766011703.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 11532023402 its reverse (20432023511), we get a palindrome (31964046913).
The spelling of 11532023402 in words is "eleven billion, five hundred thirty-two million, twenty-three thousand, four hundred two".
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