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11532153450661 is a prime number
BaseRepresentation
bin1010011111010000100111…
…1010001111000010100101
31111211110111121020220212221
42213310021322033002211
53002420322240410121
640305444222512341
72300112340654444
oct247641172170245
944743447226787
1011532153450661
113746838a86828
121363012a356b1
13658628b1a97c
142bc232c04d5b
1514ee9eedab41
hexa7d09e8f0a5

11532153450661 has 2 divisors, whose sum is σ = 11532153450662. Its totient is φ = 11532153450660.

The previous prime is 11532153450523. The next prime is 11532153450709. The reversal of 11532153450661 is 16605435123511.

11532153450661 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10995318814561 + 536834636100 = 3315919^2 + 732690^2 .

It is a cyclic number.

It is not a de Polignac number, because 11532153450661 - 221 = 11532151353509 is a prime.

It is a super-2 number, since 2×115321534506612 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11532153451661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766076725330 + 5766076725331.

It is an arithmetic number, because the mean of its divisors is an integer number (5766076725331).

Almost surely, 211532153450661 is an apocalyptic number.

It is an amenable number.

11532153450661 is a deficient number, since it is larger than the sum of its proper divisors (1).

11532153450661 is an equidigital number, since it uses as much as digits as its factorization.

11532153450661 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324000, while the sum is 43.

The spelling of 11532153450661 in words is "eleven trillion, five hundred thirty-two billion, one hundred fifty-three million, four hundred fifty thousand, six hundred sixty-one".