Base | Representation |
---|---|
bin | 110101101100111010… |
… | …0010101011110010101 |
3 | 102000200002120001211011 |
4 | 1223121310111132111 |
5 | 3342140310300023 |
6 | 124551235212221 |
7 | 11221552534354 |
oct | 1533164253625 |
9 | 360602501734 |
10 | 115323525013 |
11 | 449aa13a264 |
12 | 1a425747071 |
13 | ab4b3a22c8 |
14 | 582021d99b |
15 | 2eee65850d |
hex | 1ad9d15795 |
115323525013 has 2 divisors, whose sum is σ = 115323525014. Its totient is φ = 115323525012.
The previous prime is 115323524993. The next prime is 115323525043. The reversal of 115323525013 is 310525323511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 58251270609 + 57072254404 = 241353^2 + 238898^2 .
It is a cyclic number.
It is not a de Polignac number, because 115323525013 - 221 = 115321427861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115323525043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57661762506 + 57661762507.
It is an arithmetic number, because the mean of its divisors is an integer number (57661762507).
Almost surely, 2115323525013 is an apocalyptic number.
It is an amenable number.
115323525013 is a deficient number, since it is larger than the sum of its proper divisors (1).
115323525013 is an equidigital number, since it uses as much as digits as its factorization.
115323525013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 115323525013 its reverse (310525323511), we get a palindrome (425848848524).
The spelling of 115323525013 in words is "one hundred fifteen billion, three hundred twenty-three million, five hundred twenty-five thousand, thirteen".
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