Base | Representation |
---|---|
bin | 11010001110010001101110… |
… | …110000111000111101011011 |
3 | 120010100110201022021202010221 |
4 | 122032101232300320331123 |
5 | 110104032443424022141 |
6 | 1045142003451220511 |
7 | 33202224563253331 |
oct | 3216215660707533 |
9 | 503313638252127 |
10 | 115330320142171 |
11 | 33825350079592 |
12 | 10b27956a47737 |
13 | 4c477aa98a244 |
14 | 206a0355abb51 |
15 | d500163a8bd1 |
hex | 68e46ec38f5b |
115330320142171 has 2 divisors, whose sum is σ = 115330320142172. Its totient is φ = 115330320142170.
The previous prime is 115330320142043. The next prime is 115330320142181. The reversal of 115330320142171 is 171241023033511.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115330320142171 - 27 = 115330320142043 is a prime.
It is not a weakly prime, because it can be changed into another prime (115330320142181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57665160071085 + 57665160071086.
It is an arithmetic number, because the mean of its divisors is an integer number (57665160071086).
Almost surely, 2115330320142171 is an apocalyptic number.
115330320142171 is a deficient number, since it is larger than the sum of its proper divisors (1).
115330320142171 is an equidigital number, since it uses as much as digits as its factorization.
115330320142171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 34.
Adding to 115330320142171 its reverse (171241023033511), we get a palindrome (286571343175682).
The spelling of 115330320142171 in words is "one hundred fifteen trillion, three hundred thirty billion, three hundred twenty million, one hundred forty-two thousand, one hundred seventy-one".
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