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115332243455083 is a prime number
BaseRepresentation
bin11010001110010011100001…
…011001101111110001101011
3120010100122200100100011110111
4122032103201121233301223
5110104100413311030313
61045142522354355151
733202323336200524
oct3216234131576153
9503318610304414
10115332243455083
11338261477a7a96
1210b281b2b8bab7
134c47a26294115
14206a178bc384b
15d500ca16e43d
hex68e4e166fc6b

115332243455083 has 2 divisors, whose sum is σ = 115332243455084. Its totient is φ = 115332243455082.

The previous prime is 115332243455081. The next prime is 115332243455137. The reversal of 115332243455083 is 380554342233511.

It is a weak prime.

It is an emirp because it is prime and its reverse (380554342233511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115332243455083 - 21 = 115332243455081 is a prime.

Together with 115332243455081, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (115332243455081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57666121727541 + 57666121727542.

It is an arithmetic number, because the mean of its divisors is an integer number (57666121727542).

Almost surely, 2115332243455083 is an apocalyptic number.

115332243455083 is a deficient number, since it is larger than the sum of its proper divisors (1).

115332243455083 is an equidigital number, since it uses as much as digits as its factorization.

115332243455083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184000, while the sum is 49.

Adding to 115332243455083 its reverse (380554342233511), we get a palindrome (495886585688594).

The spelling of 115332243455083 in words is "one hundred fifteen trillion, three hundred thirty-two billion, two hundred forty-three million, four hundred fifty-five thousand, eighty-three".