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1153400425142 = 27137635986031
BaseRepresentation
bin10000110010001100000…
…001011100101010110110
311002021010110101102201112
4100302030001130222312
5122344131002101032
62241510445555022
7146221223565140
oct20621401345266
94067113342645
101153400425142
1140517751a859
12167653575a72
13849c418c484
143db79675c90
1520008b341b2
hex10c8c05cab6

1153400425142 has 16 divisors (see below), whose sum is σ = 1977401866752. Its totient is φ = 494278469160.

The previous prime is 1153400425139. The next prime is 1153400425147. The reversal of 1153400425142 is 2415240043511.

It is a junction number, because it is equal to n+sod(n) for n = 1153400425099 and 1153400425108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1153400425147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2800334 + ... + 3185697.

It is an arithmetic number, because the mean of its divisors is an integer number (123587616672).

Almost surely, 21153400425142 is an apocalyptic number.

1153400425142 is a deficient number, since it is larger than the sum of its proper divisors (824001441610).

1153400425142 is a wasteful number, since it uses less digits than its factorization.

1153400425142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5999803.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 1153400425142 its reverse (2415240043511), we get a palindrome (3568640468653).

The spelling of 1153400425142 in words is "one trillion, one hundred fifty-three billion, four hundred million, four hundred twenty-five thousand, one hundred forty-two".

Divisors: 1 2 7 14 13763 27526 96341 192682 5986031 11972062 41902217 83804434 82385744653 164771489306 576700212571 1153400425142