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115340340455303 is a prime number
BaseRepresentation
bin11010001110011011000100…
…000001010110011110000111
3120010101102120122021101122112
4122032123010001112132013
5110104214004124032203
61045150342041251235
733203031105440255
oct3216330401263607
9503342518241575
10115340340455303
11338296222a8107
1210b29892793b1b
134c4871693a502
14206a7062db5d5
15d50400e2a6d8
hex68e6c4056787

115340340455303 has 2 divisors, whose sum is σ = 115340340455304. Its totient is φ = 115340340455302.

The previous prime is 115340340455293. The next prime is 115340340455399. The reversal of 115340340455303 is 303554043043511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115340340455303 - 26 = 115340340455239 is a prime.

It is a super-3 number, since 3×1153403404553033 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115340340455203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57670170227651 + 57670170227652.

It is an arithmetic number, because the mean of its divisors is an integer number (57670170227652).

Almost surely, 2115340340455303 is an apocalyptic number.

115340340455303 is a deficient number, since it is larger than the sum of its proper divisors (1).

115340340455303 is an equidigital number, since it uses as much as digits as its factorization.

115340340455303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 115340340455303 its reverse (303554043043511), we get a palindrome (418894383498814).

The spelling of 115340340455303 in words is "one hundred fifteen trillion, three hundred forty billion, three hundred forty million, four hundred fifty-five thousand, three hundred three".