Base | Representation |
---|---|
bin | 10101011110111110… |
… | …00110111110100011 |
3 | 1002202211110010001002 |
4 | 22233133012332203 |
5 | 142110212234220 |
6 | 5144303502215 |
7 | 555553152542 |
oct | 125737067643 |
9 | 32684403032 |
10 | 11534102435 |
11 | 4989777969 |
12 | 229a8b796b |
13 | 111a78caab |
14 | 7b5bc2159 |
15 | 4778e1c75 |
hex | 2af7c6fa3 |
11534102435 has 4 divisors (see below), whose sum is σ = 13840922928. Its totient is φ = 9227281944.
The previous prime is 11534102303. The next prime is 11534102441. The reversal of 11534102435 is 53420143511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11534102435 - 28 = 11534102179 is a prime.
It is a super-3 number, since 3×115341024353 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11534102398 and 11534102407.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1153410239 + ... + 1153410248.
It is an arithmetic number, because the mean of its divisors is an integer number (3460230732).
Almost surely, 211534102435 is an apocalyptic number.
11534102435 is a deficient number, since it is larger than the sum of its proper divisors (2306820493).
11534102435 is an equidigital number, since it uses as much as digits as its factorization.
11534102435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2306820492.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 11534102435 its reverse (53420143511), we get a palindrome (64954245946).
The spelling of 11534102435 in words is "eleven billion, five hundred thirty-four million, one hundred two thousand, four hundred thirty-five".
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