Base | Representation |
---|---|
bin | 10101011110111110… |
… | …01001001001101101 |
3 | 1002202211110120020221 |
4 | 22233133021021231 |
5 | 142110213030331 |
6 | 5144304011341 |
7 | 555553220524 |
oct | 125737111155 |
9 | 32684416227 |
10 | 11534111341 |
11 | 4989783625 |
12 | 229a900b51 |
13 | 111a793b6c |
14 | 7b5bc54bb |
15 | 4778e4711 |
hex | 2af7c926d |
11534111341 has 2 divisors, whose sum is σ = 11534111342. Its totient is φ = 11534111340.
The previous prime is 11534111299. The next prime is 11534111353. The reversal of 11534111341 is 14311143511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11412648900 + 121462441 = 106830^2 + 11021^2 .
It is a cyclic number.
It is not a de Polignac number, because 11534111341 - 29 = 11534110829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11534111041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5767055670 + 5767055671.
It is an arithmetic number, because the mean of its divisors is an integer number (5767055671).
Almost surely, 211534111341 is an apocalyptic number.
It is an amenable number.
11534111341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11534111341 is an equidigital number, since it uses as much as digits as its factorization.
11534111341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 720, while the sum is 25.
Adding to 11534111341 its reverse (14311143511), we get a palindrome (25845254852).
The spelling of 11534111341 in words is "eleven billion, five hundred thirty-four million, one hundred eleven thousand, three hundred forty-one".
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