Base | Representation |
---|---|
bin | 10000110010001101010… |
… | …000110111101010101111 |
3 | 11002021011220120012100012 |
4 | 100302031100313222233 |
5 | 122344201314320403 |
6 | 2241512512123435 |
7 | 146221565550551 |
oct | 20621520675257 |
9 | 4067156505305 |
10 | 1153421245103 |
11 | 405188250136 |
12 | 16765a53657b |
13 | 849c859bb8a |
14 | 3db7c3354d1 |
15 | 2000a897ed8 |
hex | 10c8d437aaf |
1153421245103 has 4 divisors (see below), whose sum is σ = 1153439625360. Its totient is φ = 1153402864848.
The previous prime is 1153421245037. The next prime is 1153421245133. The reversal of 1153421245103 is 3015421243511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1153421245103 - 214 = 1153421228719 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1153421245103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1153421245133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9095675 + ... + 9221612.
It is an arithmetic number, because the mean of its divisors is an integer number (288359906340).
Almost surely, 21153421245103 is an apocalyptic number.
1153421245103 is a deficient number, since it is larger than the sum of its proper divisors (18380257).
1153421245103 is an equidigital number, since it uses as much as digits as its factorization.
1153421245103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18380256.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 1153421245103 its reverse (3015421243511), we get a palindrome (4168842488614).
The spelling of 1153421245103 in words is "one trillion, one hundred fifty-three billion, four hundred twenty-one million, two hundred forty-five thousand, one hundred three".
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