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115342513203 = 3136403281867
BaseRepresentation
bin110101101101011110…
…0110001010000110011
3102000201102021202201110
41223122330301100303
53342210140410303
6124553154204403
711222203120461
oct1533274612063
9360642252643
10115342513203
1144a09929385
121a42bb83703
13ab522c0018
145822963831
153001159703
hex1adaf31433

115342513203 has 8 divisors (see below), whose sum is σ = 153791690688. Its totient is φ = 76894172264.

The previous prime is 115342513183. The next prime is 115342513211. The reversal of 115342513203 is 302315243511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 115342513203 - 210 = 115342512179 is a prime.

It is not an unprimeable number, because it can be changed into a prime (115342513003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 268276 + ... + 550142.

It is an arithmetic number, because the mean of its divisors is an integer number (19223961336).

Almost surely, 2115342513203 is an apocalyptic number.

115342513203 is a deficient number, since it is larger than the sum of its proper divisors (38449177485).

115342513203 is a wasteful number, since it uses less digits than its factorization.

115342513203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 418273.

The product of its (nonzero) digits is 10800, while the sum is 30.

Adding to 115342513203 its reverse (302315243511), we get a palindrome (417657756714).

It can be divided in two parts, 1153425 and 13203, that added together give a triangular number (1166628 = T1527).

The spelling of 115342513203 in words is "one hundred fifteen billion, three hundred forty-two million, five hundred thirteen thousand, two hundred three".

Divisors: 1 3 136403 281867 409209 845601 38447504401 115342513203