Base | Representation |
---|---|
bin | 10101011111000000… |
… | …00111100100001101 |
3 | 1002202211221112221101 |
4 | 22233200013210031 |
5 | 142110244220424 |
6 | 5144313303101 |
7 | 555555334045 |
oct | 125740074415 |
9 | 32684845841 |
10 | 11534366989 |
11 | 4989938702 |
12 | 229aa04a91 |
13 | 111a853332 |
14 | 7b5c50725 |
15 | 477945344 |
hex | 2af80790d |
11534366989 has 2 divisors, whose sum is σ = 11534366990. Its totient is φ = 11534366988.
The previous prime is 11534366969. The next prime is 11534367007. The reversal of 11534366989 is 98966343511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10066710889 + 1467656100 = 100333^2 + 38310^2 .
It is a cyclic number.
It is not a de Polignac number, because 11534366989 - 223 = 11525978381 is a prime.
It is a super-2 number, since 2×115343669892 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11534366959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5767183494 + 5767183495.
It is an arithmetic number, because the mean of its divisors is an integer number (5767183495).
Almost surely, 211534366989 is an apocalyptic number.
It is an amenable number.
11534366989 is a deficient number, since it is larger than the sum of its proper divisors (1).
11534366989 is an equidigital number, since it uses as much as digits as its factorization.
11534366989 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4199040, while the sum is 55.
The spelling of 11534366989 in words is "eleven billion, five hundred thirty-four million, three hundred sixty-six thousand, nine hundred eighty-nine".
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