1153440433 has 4 divisors (see below), whose sum is σ = 1153588288. Its totient is φ = 1153292580.

The previous prime is 1153440389. The next prime is 1153440437. The reversal of 1153440433 is 3340443511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3340443511 = 113 ⋅29561447.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1153440433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1153440437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61533 + ... + 78058.

It is an arithmetic number, because the mean of its divisors is an integer number (288397072).

Almost surely, 2^1153440433 is an apocalyptic number.

It is an amenable number.

1153440433 is a deficient number, since it is larger than the sum of its proper divisors (147855).

1153440433 is an equidigital number, since it uses as much as digits as its factorization.

1153440433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147854.

The product of its (nonzero) digits is 8640, while the sum is 28.

The square root of 1153440433 is about 33962.3384501126. The cubic root of 1153440433 is about 1048.7332972773.

Adding to 1153440433 its reverse (3340443511), we get a palindrome (4493883944).

The spelling of 1153440433 in words is "one billion, one hundred fifty-three million, four hundred forty thousand, four hundred thirty-three".