Base | Representation |
---|---|
bin | 110101101101101110… |
… | …1010001100111110001 |
3 | 102000202000022200112121 |
4 | 1223123131101213301 |
5 | 3342214331044403 |
6 | 124554100554241 |
7 | 11222335420462 |
oct | 1533335214761 |
9 | 360660280477 |
10 | 115351034353 |
11 | 44a13719455 |
12 | 1a4329b2981 |
13 | ab53cb4719 |
14 | 5823b40d69 |
15 | 3001c8e3bd |
hex | 1adb7519f1 |
115351034353 has 2 divisors, whose sum is σ = 115351034354. Its totient is φ = 115351034352.
The previous prime is 115351034287. The next prime is 115351034389. The reversal of 115351034353 is 353430153511.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62548509409 + 52802524944 = 250097^2 + 229788^2 .
It is a cyclic number.
It is not a de Polignac number, because 115351034353 - 217 = 115350903281 is a prime.
It is a super-2 number, since 2×1153510343532 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115351034453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57675517176 + 57675517177.
It is an arithmetic number, because the mean of its divisors is an integer number (57675517177).
Almost surely, 2115351034353 is an apocalyptic number.
It is an amenable number.
115351034353 is a deficient number, since it is larger than the sum of its proper divisors (1).
115351034353 is an equidigital number, since it uses as much as digits as its factorization.
115351034353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 34.
Adding to 115351034353 its reverse (353430153511), we get a palindrome (468781187864).
The spelling of 115351034353 in words is "one hundred fifteen billion, three hundred fifty-one million, thirty-four thousand, three hundred fifty-three".
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