11535541133141 has 4 divisors (see below), whose sum is σ = 11535562977312. Its totient is φ = 11535519288972.

The previous prime is 11535541133113. The next prime is 11535541133177. The reversal of 11535541133141 is 14133114553511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11535541133141 - 2²² = 11535536938837 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11535541133095 and 11535541133104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11535541135141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10109825 + ... + 11192838.

It is an arithmetic number, because the mean of its divisors is an integer number (2883890744328).

Almost surely, 2^{11535541133141} is an apocalyptic number.

It is an amenable number.

11535541133141 is a deficient number, since it is larger than the sum of its proper divisors (21844171).

11535541133141 is an equidigital number, since it uses as much as digits as its factorization.

11535541133141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21844170.

The product of its digits is 54000, while the sum is 38.

Adding to 11535541133141 its reverse (14133114553511), we get a palindrome (25668655686652).

The spelling of 11535541133141 in words is "eleven trillion, five hundred thirty-five billion, five hundred forty-one million, one hundred thirty-three thousand, one hundred forty-one".