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1153554313481 is a prime number
BaseRepresentation
bin10000110010010101001…
…100011111000100001001
311002021112011221202211122
4100302111030133010021
5122344434401012411
62241534024205025
7146225102611163
oct20622514370411
94067464852748
101153554313481
114052463783a9
12167697009775
1384a1a02016b
143db91c93933
15200173d09db
hex10c9531f109

1153554313481 has 2 divisors, whose sum is σ = 1153554313482. Its totient is φ = 1153554313480.

The previous prime is 1153554313447. The next prime is 1153554313489. The reversal of 1153554313481 is 1843134553511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 606242875456 + 547311438025 = 778616^2 + 739805^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1153554313481 is a prime.

It is a super-2 number, since 2×11535543134812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1153554313489) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576777156740 + 576777156741.

It is an arithmetic number, because the mean of its divisors is an integer number (576777156741).

Almost surely, 21153554313481 is an apocalyptic number.

It is an amenable number.

1153554313481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153554313481 is an equidigital number, since it uses as much as digits as its factorization.

1153554313481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432000, while the sum is 44.

Adding to 1153554313481 its reverse (1843134553511), we get a palindrome (2996688866992).

The spelling of 1153554313481 in words is "one trillion, one hundred fifty-three billion, five hundred fifty-four million, three hundred thirteen thousand, four hundred eighty-one".