Base | Representation |
---|---|
bin | 1010011111100111000010… |
… | …0110101111111011000101 |
3 | 1111212001001000000112200121 |
4 | 2213321300212233323011 |
5 | 3003020133332104023 |
6 | 40312321315341541 |
7 | 2300414433245431 |
oct | 247716046577305 |
9 | 44761030015617 |
10 | 11538171363013 |
11 | 3749346a31409 |
12 | 13642122b18b1 |
13 | 659077818859 |
14 | 2bc6441579c1 |
15 | 1502034b0d5d |
hex | a7e709afec5 |
11538171363013 has 2 divisors, whose sum is σ = 11538171363014. Its totient is φ = 11538171363012.
The previous prime is 11538171362947. The next prime is 11538171363041. The reversal of 11538171363013 is 31036317183511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8322544153924 + 3215627209089 = 2884882^2 + 1793217^2 .
It is a cyclic number.
It is not a de Polignac number, because 11538171363013 - 229 = 11537634492101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11538171363113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5769085681506 + 5769085681507.
It is an arithmetic number, because the mean of its divisors is an integer number (5769085681507).
Almost surely, 211538171363013 is an apocalyptic number.
It is an amenable number.
11538171363013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11538171363013 is an equidigital number, since it uses as much as digits as its factorization.
11538171363013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 43.
The spelling of 11538171363013 in words is "eleven trillion, five hundred thirty-eight billion, one hundred seventy-one million, three hundred sixty-three thousand, thirteen".
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