11540054640133 has 2 divisors, whose sum is σ = 11540054640134. Its totient is φ = 11540054640132.

The previous prime is 11540054639977. The next prime is 11540054640173. The reversal of 11540054640133 is 33104645004511.

11540054640133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10909234285569 + 630820354564 = 3302913^2 + 794242^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11540054640133 is a prime.

It is a super-2 number, since 2×11540054640133² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11540054640092 and 11540054640101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11540054640173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770027320066 + 5770027320067.

It is an arithmetic number, because the mean of its divisors is an integer number (5770027320067).

Almost surely, 2^{11540054640133} is an apocalyptic number.

It is an amenable number.

11540054640133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11540054640133 is an equidigital number, since it uses as much as digits as its factorization.

11540054640133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 11540054640133 its reverse (33104645004511), we get a palindrome (44644699644644).

The spelling of 11540054640133 in words is "eleven trillion, five hundred forty billion, fifty-four million, six hundred forty thousand, one hundred thirty-three".