11540103 has 4 divisors (see below), whose sum is σ = 15386808. Its totient is φ = 7693400.

The previous prime is 11540101. The next prime is 11540107. The reversal of 11540103 is 30104511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30104511 = 3 ⋅10034837.

It is a cyclic number.

It is not a de Polignac number, because 11540103 - 2¹ = 11540101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11540101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1923348 + ... + 1923353.

It is an arithmetic number, because the mean of its divisors is an integer number (3846702).

Almost surely, 2^11540103 is an apocalyptic number.

11540103 is a deficient number, since it is larger than the sum of its proper divisors (3846705).

11540103 is an equidigital number, since it uses as much as digits as its factorization.

11540103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3846704.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 11540103 is about 3397.0727104376. The cubic root of 11540103 is about 225.9799431387.

Adding to 11540103 its reverse (30104511), we get a palindrome (41644614).

The spelling of 11540103 in words is "eleven million, five hundred forty thousand, one hundred three".