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11540224213 = 71679871877
BaseRepresentation
bin10101011111101100…
…11101100011010101
31002210020222010112121
422233312131203111
5142113244133323
65145043015541
7555656200360
oct125766354325
932706863477
1011540224213
114992179291
1222a096a5b1
13111bb2434b
147b69370d7
15478200a5d
hex2afd9d8d5

11540224213 has 8 divisors (see below), whose sum is σ = 13267804032. Its totient is φ = 9832388496.

The previous prime is 11540224211. The next prime is 11540224219. The reversal of 11540224213 is 31242204511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11540224213 - 21 = 11540224211 is a prime.

It is a super-2 number, since 2×115402242132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11540224211) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4934770 + ... + 4937107.

It is an arithmetic number, because the mean of its divisors is an integer number (1658475504).

Almost surely, 211540224213 is an apocalyptic number.

It is an amenable number.

11540224213 is a deficient number, since it is larger than the sum of its proper divisors (1727579819).

11540224213 is an equidigital number, since it uses as much as digits as its factorization.

11540224213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9872051.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 11540224213 its reverse (31242204511), we get a palindrome (42782428724).

The spelling of 11540224213 in words is "eleven billion, five hundred forty million, two hundred twenty-four thousand, two hundred thirteen".

Divisors: 1 7 167 1169 9871877 69103139 1648603459 11540224213