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115403143 is a prime number
BaseRepresentation
bin1101110000011…
…10100110000111
322001011002100111
412320032212013
5214020400033
615241253451
72600624212
oct670164607
9261132314
10115403143
115a1620a9
1232794287
131aba77ab
1411480779
15a1e87cd
hex6e0e987

115403143 has 2 divisors, whose sum is σ = 115403144. Its totient is φ = 115403142.

The previous prime is 115403087. The next prime is 115403147. The reversal of 115403143 is 341304511.

It is a strong prime.

It is an emirp because it is prime and its reverse (341304511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115403143 - 29 = 115402631 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115403147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701571 + 57701572.

It is an arithmetic number, because the mean of its divisors is an integer number (57701572).

Almost surely, 2115403143 is an apocalyptic number.

115403143 is a deficient number, since it is larger than the sum of its proper divisors (1).

115403143 is an equidigital number, since it uses as much as digits as its factorization.

115403143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 115403143 is about 10742.5854895365. The cubic root of 115403143 is about 486.8620002044.

Adding to 115403143 its reverse (341304511), we get a palindrome (456707654).

The spelling of 115403143 in words is "one hundred fifteen million, four hundred three thousand, one hundred forty-three".