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11540315201 is a prime number
BaseRepresentation
bin10101011111101101…
…10011110001000001
31002210021010202100112
422233312303301001
5142113310041301
65145045001105
7555660026552
oct125766636101
932707122315
1011540315201
114992230688
1222a09b3195
13111bb5689c
147b695c329
1547821c9bb
hex2afdb3c41

11540315201 has 2 divisors, whose sum is σ = 11540315202. Its totient is φ = 11540315200.

The previous prime is 11540315123. The next prime is 11540315231. The reversal of 11540315201 is 10251304511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11131305025 + 409010176 = 105505^2 + 20224^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11540315201 is a prime.

It is not a weakly prime, because it can be changed into another prime (11540315231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770157600 + 5770157601.

It is an arithmetic number, because the mean of its divisors is an integer number (5770157601).

Almost surely, 211540315201 is an apocalyptic number.

It is an amenable number.

11540315201 is a deficient number, since it is larger than the sum of its proper divisors (1).

11540315201 is an equidigital number, since it uses as much as digits as its factorization.

11540315201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 11540315201 its reverse (10251304511), we get a palindrome (21791619712).

The spelling of 11540315201 in words is "eleven billion, five hundred forty million, three hundred fifteen thousand, two hundred one".