11540315401 has 2 divisors, whose sum is σ = 11540315402. Its totient is φ = 11540315400.

The previous prime is 11540315393. The next prime is 11540315417. The reversal of 11540315401 is 10451304511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9006199801 + 2534115600 = 94901^2 + 50340^2 .

It is an emirp because it is prime and its reverse (10451304511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11540315401 - 2³ = 11540315393 is a prime.

It is not a weakly prime, because it can be changed into another prime (11540315201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770157700 + 5770157701.

It is an arithmetic number, because the mean of its divisors is an integer number (5770157701).

Almost surely, 2^11540315401 is an apocalyptic number.

It is an amenable number.

11540315401 is a deficient number, since it is larger than the sum of its proper divisors (1).

11540315401 is an equidigital number, since it uses as much as digits as its factorization.

11540315401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 11540315401 its reverse (10451304511), we get a palindrome (21991619912).

The spelling of 11540315401 in words is "eleven billion, five hundred forty million, three hundred fifteen thousand, four hundred one".