Base | Representation |
---|---|
bin | 10101011111101101… |
… | …10110010010101111 |
3 | 1002210021011021112212 |
4 | 22233312312102233 |
5 | 142113310404201 |
6 | 5145045121035 |
7 | 555660101666 |
oct | 125766662257 |
9 | 32707137485 |
10 | 11540325551 |
11 | 4992238437 |
12 | 22a09b917b |
13 | 111bb5b501 |
14 | 7b6961ddd |
15 | 478220abb |
hex | 2afdb64af |
11540325551 has 2 divisors, whose sum is σ = 11540325552. Its totient is φ = 11540325550.
The previous prime is 11540325539. The next prime is 11540325571. The reversal of 11540325551 is 15552304511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11540325551 - 26 = 11540325487 is a prime.
It is a super-2 number, since 2×115403255512 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11540325571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770162775 + 5770162776.
It is an arithmetic number, because the mean of its divisors is an integer number (5770162776).
Almost surely, 211540325551 is an apocalyptic number.
11540325551 is a deficient number, since it is larger than the sum of its proper divisors (1).
11540325551 is an equidigital number, since it uses as much as digits as its factorization.
11540325551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 32.
The spelling of 11540325551 in words is "eleven billion, five hundred forty million, three hundred twenty-five thousand, five hundred fifty-one".
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